by Den Blonde Ulven
July 19, 2023
My father and I performed some optic experiments near Virginia Beach in Norfolk, Virginia. The goal of this event was to check the hypothesis: can objects be seen further than they should be able due to the curvature of the Earth?
We were standing on Ocean View Beach close to East Ocean View Beach- coordinates 36.933410, -76.201875. Three pieces of equipment were utilized- a Nikon P1000 camera, a tripod, and an SD memory card for the camera. This camera was capable of recording while shooting a video and simultaneously zooming in great distances. The P1000 is what captured the videos shown.
The weather was partly cloudy, no rain, and slightly hazy. These are not ideal conditions due to the haze. Yet even under these non-ideal conditions, objects that have been zoomed in upon are distinguishable.
We used a website to determine the location of cargo ships on a map in near real-time:
This allowed us to estimate where the ships were. We then used a feature on Google Maps called “measure” to connect our location with the ships’. This gave us an approximate distance of which I estimate is accurate within a range of (+-)0.2 miles.
We used the equation of 8 inches per mile squared (y = 8 * x^2) as a very-close approximation to calculate the curvature of the earth, where x is the distance away from a viewed object in miles, and y is the amount of height lost in inches. This equation makes a parabola, whereas the more exact equation to use is circular. The parabolic equation diverges from the circular equation at thousands of miles away. For this experiment, we were concerned with possible miles, not even tens of miles. This difference is so negligible as to serve this experiment’s purposes.
To give a few examples, at 1 mile away, 8 inches of height is lost. 2 miles away, 32 inches is lost. 3 miles, 72 inches, etc. This is offset by the point of view of the viewer being x feet above the surface. In all of the shown videos, the camera is 6 feet above the water. When factoring in this offset, simply subtract 6 feet after calculating the amount of height lost.
The full equation is
y = [(8 * x^2) / 12] – 6
where x is the amount of miles away from the viewed object
To use some video examples, the most significant are those at a distance of 6+ miles. The bridge in the following video is 6.4 miles away; the boat 6.5:
Taking the above boat with the boat being 6.5 miles away. The math looks like this:
[(8 * 6.5^2) / 12] – 6 = 22.16 feet
So, at a distance of 6.5 miles away, we should lose about 22 feet of height. In the above example, we can see the entire side of the ship all the way down to the water line. In other video examples, the boat is clearer:
Where the water meets the boat is clear, and the entire shape is clearly shown. In the 6.5 miles example, the entire shape is still visible. The water meeting the boat might not be clear, but the lack of lost shape shows how little of the boat has been lost to the horizon. Typical cargo ships in the US do not exceed 116 feet in height above the water level. Thus, we should lose 1/5 of the boat’s bottom, and yet we see much more.
We also captured video with a pier as an object. The end of the pier is 3.6 miles away from our position:
Taking the above pier example, the pier is 3.6 miles away. The math looks like this:
[(8 * 3.6^2) / 12] – 6 = 2.64 feet
So, at a distance of 3.6 miles away, we should lose 2.64 feet of height. The footage is clear- we can see where the water meets the supports of the pier.
There are a few videos in which the distance to the viewed objects are unknown. We were unable to identify exactly what was viewed and matching it to a map. The haze also significantly affects the viewing quality of these objects. What is known is that they are well beyond 6.5 miles away. One is a bridge with many pillar supports:
The other appears to be a white building, possibly next to the water:
Because these objects are of unknown distances, no exact calculation can be made. If anyone can identify what/where this building or bridge are, please share them or the coordinates with me.
There is another phenomenon of which has hitherto been unaccounted. That is the phenomenon of refraction, or the bending of light. The argument is that the medium light travels though bends it, so any object that we view is actually slightly distorted and is being warped around the curvature. This adds back some amount of lost height an object experiences as it moves away from a point due to the curvature. I have read many different accounts giving a range of values as to how much height is added back due to refraction. It apparently deals with the position of the sun, particles in the air, and other factors. I am unsure how to account for this in my equations. If this is known by someone, please share.
Several additional videos were captured, but either the positioning was not ideal, the distance too small to be significant, or other factors prevented them from being stellar examples. These have been included here for completeness:
In conclusion, I have seen with my own eyes, via technology generally available, further than I should be able to see. This confirms to me that the Earth is not a ball with a radius of 3,963 miles. It could be a ball of significantly larger radius, or a flat plane, or a turtle with a calendar on the back of its shell. What it is absolutely not is a ball the size NASA and Science Religionists claim it to be. However, based on our work and the work of others performing different experiments, pilot testimonies, and other factors, I do not believe it a ball at all.
I am not a photographer.
It is very difficult to precisely and smoothly record clearly while zoomed in such extreme distances.
The 8 inches per mile squared came from various Earth skeptics. But this video does a good job visualizing the math and showing that the approximation eventually breaks.
Regarding refraction- I do not necessarily believe the mainstream view of this phenomenon. It seems like rationalization to account for people being able to see further than they normally should. Even still, I think that at far enough distances, the amount we are able to see absolutely dwarfs the maximum amount of height added back by refraction.
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